document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=381469>Question 381469</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The ratio of the weight of copper to the weight of zinc in a coin is 1/38. If 55 kg of zinc is being turned into coins, how much copper is needed? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #270635 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley79><B>checkley79(3341)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley79><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=270635\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/38=x/55 cross multiply.<BR>\n" );
document.write( "38x=55<BR>\n" );
document.write( "x=55/38<BR>\n" );
document.write( "x=1.48 oz. of copper is needed.<BR>\n" );
document.write( " </SPAN>\n" );
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