document.write( "Question 381513: 4y=2(x+1)^2-1
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Algebra.Com's Answer #270594 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "4y=2(x+1)^2-1
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document.write( " y = (1/2)(x+1)^2 - 1/4
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document.write( "the vertex form of a parabola,  where(h,k) is the vertex
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document.write( " Pt(-1,-1/4) is the vertex
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document.write( "y-intercept, when x  = 0
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document.write( "y = (1/2)*1 - 1/4
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document.write( "y = (1/2) Pt(0,1/4) the y intercept
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document.write( "x-intercept, when y = 0
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document.write( " 0 = (1/2)(x+1)^2 - 1/4
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document.write( " 1/4 = (1/2)(x+1)^2 
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document.write( "  2/4 = x^2 + 2x + 1
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document.write( "   0 = x^2 + 2x + 1/2
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