document.write( "Question 381445: The probability distribution of a discrete random variable X is shown below \r
\n" ); document.write( "\n" ); document.write( "x 0 1 2 3
\n" ); document.write( "p(x) 0.25 0.40 0.20 0.15\r
\n" ); document.write( "\n" ); document.write( "1) Find the expected value of X and the standard deviation of X
\n" ); document.write( "2) Suppose another random variable, Y = -3X-2. Then find the expected value of Y and the standard deviation of Y
\n" ); document.write( "-3X-2)
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Algebra.Com's Answer #270560 by robertb(5830)\"\" \"About 
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1) \"mu+=+0%2A0.25+%2B+1%2A0.40+%2B+2%2A0.20+%2B+3%2A0.15+=+0.40+%2B+0.40+%2B+0.45+=+1.25\"
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\n" ); document.write( "\n" ); document.write( "2) E(-3X-2) = -3E(X) - 2 = -3*1.25-2 = -5.75.
\n" ); document.write( "\"Var%28-3X+-+2%29+=+9Var%28X%29\". This means \"sqrt%28Var%28-3X+-+2%29%29+=+3sqrt%28Var%28X%29%29+=+3sigma\". Hence standard deviation of Y = -3X-2 is 3*0.99373 = 2.98119.
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