document.write( "Question 381445: The probability distribution of a discrete random variable X is shown below \r
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document.write( "x 0 1 2 3
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document.write( "p(x) 0.25 0.40 0.20 0.15\r
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document.write( "1) Find the expected value of X and the standard deviation of X
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document.write( "2) Suppose another random variable, Y = -3X-2. Then find the expected value of Y and the standard deviation of Y
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document.write( "-3X-2) \n" );
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Algebra.Com's Answer #270560 by robertb(5830)![]() ![]() You can put this solution on YOUR website! 1) \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2) E(-3X-2) = -3E(X) - 2 = -3*1.25-2 = -5.75. \n" ); document.write( " |