document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=378973>Question 378973</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the central angle theta of a circle with radius 9 inches intercepts an arc 20 inches, find theta </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #270555 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=270555\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From the (circular) arc length formula, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s+=+r%2Atheta ALIGN=MIDDLE  ALT=\"s+=+r%2Atheta\"   DISABLED_style= \"max-width:90%; height:auto;\" >, use it to solve for <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=theta ALIGN=MIDDLE  ALT=\"theta\"   DISABLED_style= \"max-width:90%; height:auto;\" >:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=theta+=+s%2Fr+=+20%2F9+ ALIGN=MIDDLE  ALT=\"theta+=+s%2Fr+=+20%2F9+\"   DISABLED_style= \"max-width:90%; height:auto;\" >radians.  In degrees, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2820%2F9%29%2A%28180%2Fpi%29+=+400%2Fpi ALIGN=MIDDLE  ALT=\"%2820%2F9%29%2A%28180%2Fpi%29+=+400%2Fpi\"   DISABLED_style= \"max-width:90%; height:auto;\" > degrees. </SPAN>\n" );
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