document.write( "Question 41926: Can someone help me on this problem?
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document.write( " I have two parallel lines, I have a line going down the middle at a slant.
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document.write( " On the top line I have a in the left hand corner and b on the other side on the right hand corner. On the bottom horizonal line I have a in the right moddle corner . Below that line in the acute circle it is 56 degrees.\r
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document.write( " I need to find mc\r
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document.write( " Thanks,
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document.write( " Sher \n" );
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Algebra.Com's Answer #27055 by AnlytcPhil(1806)![]() ![]() You can put this solution on YOUR website! If you have this\r\n" ); document.write( "\r\n" ); document.write( " \\r\n" ); document.write( " \\r\n" ); document.write( " _________\_____________________\r\n" ); document.write( " \\r\n" ); document.write( " \\r\n" ); document.write( " \\r\n" ); document.write( " _________\_________________\r\n" ); document.write( " \56°\r\n" ); document.write( " \\r\n" ); document.write( " \\r\n" ); document.write( "\r\n" ); document.write( "Then its opposite angle is also 56°\r\n" ); document.write( "\r\n" ); document.write( " \\r\n" ); document.write( " \\r\n" ); document.write( " _________\_____________________\r\n" ); document.write( " \\r\n" ); document.write( " \\r\n" ); document.write( " \\r\n" ); document.write( " _____56°_\_________________\r\n" ); document.write( " \56°\r\n" ); document.write( " \\r\n" ); document.write( " \\r\n" ); document.write( "\r\n" ); document.write( "The opposite interior angles and exterior angles \r\n" ); document.write( "to the 56° angles are also 56° \r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " \\r\n" ); document.write( " \\r\n" ); document.write( " _____56°_\_____________________\r\n" ); document.write( " \56°\r\n" ); document.write( " \\r\n" ); document.write( " \\r\n" ); document.write( " _____56°_\_________________\r\n" ); document.write( " \56°\r\n" ); document.write( " \\r\n" ); document.write( " \\r\n" ); document.write( "\r\n" ); document.write( "The other angles are supplementary to 56°, that is\r\n" ); document.write( "they are found by subtracting 56° from 180°.\r\n" ); document.write( "\r\n" ); document.write( "180° - 56° = 124°\r\n" ); document.write( "\r\n" ); document.write( " \\r\n" ); document.write( " \\r\n" ); document.write( " _____56°_\124°______________\r\n" ); document.write( " 124°\56°\r\n" ); document.write( " \\r\n" ); document.write( " \\r\n" ); document.write( " _____56°_\124°_________________\r\n" ); document.write( " 124°\56°\r\n" ); document.write( " \\r\n" ); document.write( " \\r\n" ); document.write( "\r\n" ); document.write( "Edwin\r\n" ); document.write( "AnlytcPhil@aol.com\n" ); document.write( " |