document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41890>Question 41890</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the line containing the point (-1,3) and perpendicular to hte line 2x+4y=-1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #27054 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=27054\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We need a line perpendicular to<BR>\n" );
document.write( "2x + 4y = -1<BR>\n" );
document.write( "Let us find the slope of this line first...<BR>\n" );
document.write( "4y = -2x - 1<BR>\n" );
document.write( "y = (-1/2)x - 1/4<BR>\n" );
document.write( "The slope here is -1/2.<BR>\n" );
document.write( "The slope of the perpendicular to it is the negative reciprocal, or +2.<BR>\n" );
document.write( "Now use the point-slope form<BR>\n" );
document.write( "y - y1 = m(x - x1)<BR>\n" );
document.write( "y - 3 = 2(x + 1)<BR>\n" );
document.write( "y - 3 = 2x + 2<BR>\n" );
document.write( "y = 2x + 5 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );