document.write( "Question 381370: When a plane flies into the wind, it can travel 3,000 km in 6 hours. When it flies with the wind, it can travel the same distance in 5 hours. Find the rate of the plane in still air and the rate of the wind. \n" ); document.write( "
Algebra.Com's Answer #270532 by mananth(16946)\"\" \"About 
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speed of plane = p
\n" ); document.write( "speed of wind = w
\n" ); document.write( "..
\n" ); document.write( "tail wind speed = p+w mph
\n" ); document.write( "against wind speed = p-w
\n" ); document.write( "..
\n" ); document.write( "distance tailwind = 3000 miles
\n" ); document.write( "time = 5 hours
\n" ); document.write( "..
\n" ); document.write( "t=d/r
\n" ); document.write( "5=3000/(p+w)
\n" ); document.write( "multiply by (p+w)
\n" ); document.write( "5(p+w)=3000
\n" ); document.write( "/5
\n" ); document.write( "p+w = 600...................1
\n" ); document.write( "..
\n" ); document.write( "Against wind
\n" ); document.write( "6=3000/(p-w)
\n" ); document.write( "6(p-w)=3000
\n" ); document.write( "/6
\n" ); document.write( "p-w=500.....................2
\n" ); document.write( "..
\n" ); document.write( "add 1&2
\n" ); document.write( "2p=600+500
\n" ); document.write( "2p=1100
\n" ); document.write( "/2
\n" ); document.write( "p=550 mph
\n" ); document.write( "...
\n" ); document.write( "p+w = 600
\n" ); document.write( "550+w=600
\n" ); document.write( "w=50 mph
\n" ); document.write( "..
\n" ); document.write( "m.ananth@hotmail.ca\r
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