document.write( "Question 381370: When a plane flies into the wind, it can travel 3,000 km in 6 hours. When it flies with the wind, it can travel the same distance in 5 hours. Find the rate of the plane in still air and the rate of the wind. \n" ); document.write( "
Algebra.Com's Answer #270532 by mananth(16946)![]() ![]() You can put this solution on YOUR website! speed of plane = p \n" ); document.write( "speed of wind = w \n" ); document.write( ".. \n" ); document.write( "tail wind speed = p+w mph \n" ); document.write( "against wind speed = p-w \n" ); document.write( ".. \n" ); document.write( "distance tailwind = 3000 miles \n" ); document.write( "time = 5 hours \n" ); document.write( ".. \n" ); document.write( "t=d/r \n" ); document.write( "5=3000/(p+w) \n" ); document.write( "multiply by (p+w) \n" ); document.write( "5(p+w)=3000 \n" ); document.write( "/5 \n" ); document.write( "p+w = 600...................1 \n" ); document.write( ".. \n" ); document.write( "Against wind \n" ); document.write( "6=3000/(p-w) \n" ); document.write( "6(p-w)=3000 \n" ); document.write( "/6 \n" ); document.write( "p-w=500.....................2 \n" ); document.write( ".. \n" ); document.write( "add 1&2 \n" ); document.write( "2p=600+500 \n" ); document.write( "2p=1100 \n" ); document.write( "/2 \n" ); document.write( "p=550 mph \n" ); document.write( "... \n" ); document.write( "p+w = 600 \n" ); document.write( "550+w=600 \n" ); document.write( "w=50 mph \n" ); document.write( ".. \n" ); document.write( "m.ananth@hotmail.ca\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |