document.write( "Question 381159: What are the possible values of x domain: [0,2pi). \r
\n" );
document.write( "\n" );
document.write( "4sin^3(x) + 2sin^2(x) = 2sin(x) + 1\r
\n" );
document.write( "\n" );
document.write( "So far I've:\r
\n" );
document.write( "\n" );
document.write( "set equal to zero:
\n" );
document.write( "4sin^3(x) + 2sin^2(x) + 2sin(x) + 1 = 0 \n" );
document.write( "
Algebra.Com's Answer #270515 by richard1234(7193)![]() ![]() You can put this solution on YOUR website! First of all when you set everything equal to zero you should obtain\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let a = sin x. The equation then becomes\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is equivalent to \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solving, we obtain a = -1/2, sqrt(2)/2, and -sqrt(2)/2. All of these values are between -1 and 1, so we can find sin^-1 of each of these angles to find all values for x:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " |