document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=381398>Question 381398</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Brianna's family spent $134 on 2 adults tickets and 3 youth tickets at an amusement park. Max's family spent $146 on 3 adult ticktes and 2 youth tickets. What is the price of a youth ticket? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #270501 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=270501\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the price of an adult ticket and y be the price of a youth ticket. We have\r<BR>\n" );
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document.write( "2x + 3y = 134<BR>\n" );
document.write( "3x + 2y = 146\r<BR>\n" );
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document.write( "Adding the two equations and dividing by 5, we obtain\r<BR>\n" );
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document.write( "x + y = 56\r<BR>\n" );
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document.write( "Since 2x + 3y = 2(x + y) + y = 2(56) + y = 112 + y we can substitute into the first equation to get\r<BR>\n" );
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document.write( "112 + y = 134 --> y = 22\r<BR>\n" );
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document.write( "Therefore the price of a youth ticket is $22. </SPAN>\n" );
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