document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=381279>Question 381279</A>: <I><SPAN STYLE=\"word-break: break-all;\"> given 300 meters, what is the maximum rectangular area that can be fenced off? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #270462 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=270462\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The optimal area of a rectangle with a given perimeter is a square (this can be proven using introductory calculus). Therefore the side length of such a square is 75 m, so the area is (75 m)^2 = 5625 m^2. </SPAN>\n" );
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