document.write( "Question 41867This question is from textbook
\n" ); document.write( ": A plane flies 720 mi against a steady 30-mi/h headwind and then returns to the same point with the wind. If the entire trip takes 10 h, what is the plane's speed in still air?\r
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Algebra.Com's Answer #27046 by fractalier(6550)\"\" \"About 
You can put this solution on YOUR website!
In problems like this, we always use distance = rate * time, or D = RT.
\n" ); document.write( "Thus T = D/R. Let R be the plane's speed in still air.
\n" ); document.write( "Going against the wind, we have
\n" ); document.write( "T1 = 720 / (R - 30) and
\n" ); document.write( "T2 = 720 / (R + 30)
\n" ); document.write( "But these two times add to 10 hours, so we have
\n" ); document.write( "720 / (R - 30) + 720 / (R + 30) = 10
\n" ); document.write( "Now multiply everything by (R+30)(R-30) to clear fractions...
\n" ); document.write( "720(R+30) + 720(R-30) = 10(R+30)(R-30)
\n" ); document.write( "Now solve for R...
\n" ); document.write( "720R + 21600 + 720R - 21600 = 10(R^2 - 900)
\n" ); document.write( "1440R = 10(R^2 - 900)
\n" ); document.write( "144R = R^2 - 900
\n" ); document.write( "R^2 - 144R - 900 = 0
\n" ); document.write( "(R - 150)(R + 6) = 0
\n" ); document.write( "R = 150 mph
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