document.write( "Question 381290: A migrating elephant herd started movin at a rate of six miles per hour.One elephant stood still and was left behind. Then this stray elephant sensed danger andbehan running at a rat of ten miles per hour to reach the herd. The stray caught up in five minutes.How long ( in hours ) did the stray run to catch up?How fardid it run?
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Algebra.Com's Answer #270438 by mananth(16946)![]() ![]() You can put this solution on YOUR website! A migrating elephant herd started movin at a rate of six miles per hour.One elephant stood still and was left behind. Then this stray elephant sensed danger andbehan running at a rat of ten miles per hour to reach the herd. The stray caught up in five minutes.How long ( in hours ) did the stray run to catch up?How fardid it run? \n" ); document.write( "... \n" ); document.write( "rate = 6 mph. \n" ); document.write( "rate of stray elephant = 10 mph. \n" ); document.write( "since they are moving in same direction subtract the rates \n" ); document.write( "10-6 = 4mph. is the catch up speed. \n" ); document.write( ".. \n" ); document.write( "distance = r*t \n" ); document.write( "distance = 4 * 5/60 \n" ); document.write( "distance = 20/60 \n" ); document.write( "distance = 1/3 mile. \n" ); document.write( "... \n" ); document.write( "distance run by stray = 1/3 mile. \n" ); document.write( "rate = 10 mph \n" ); document.write( "time = (1/3) / 10 \n" ); document.write( "time = 1/3 * (1/10) \n" ); document.write( "time = 1/30 hour \n" ); document.write( "time the stray ran = 0.0333 hours \n" ); document.write( ".. \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( ".. \n" ); document.write( " \n" ); document.write( " |