document.write( "Question 381290: A migrating elephant herd started movin at a rate of six miles per hour.One elephant stood still and was left behind. Then this stray elephant sensed danger andbehan running at a rat of ten miles per hour to reach the herd. The stray caught up in five minutes.How long ( in hours ) did the stray run to catch up?How fardid it run?
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Algebra.Com's Answer #270438 by mananth(16946)\"\" \"About 
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A migrating elephant herd started movin at a rate of six miles per hour.One elephant stood still and was left behind. Then this stray elephant sensed danger andbehan running at a rat of ten miles per hour to reach the herd. The stray caught up in five minutes.How long ( in hours ) did the stray run to catch up?How fardid it run?
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\n" ); document.write( "rate = 6 mph.
\n" ); document.write( "rate of stray elephant = 10 mph.
\n" ); document.write( "since they are moving in same direction subtract the rates
\n" ); document.write( "10-6 = 4mph. is the catch up speed.
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\n" ); document.write( "distance = r*t
\n" ); document.write( "distance = 4 * 5/60
\n" ); document.write( "distance = 20/60
\n" ); document.write( "distance = 1/3 mile.
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\n" ); document.write( "distance run by stray = 1/3 mile.
\n" ); document.write( "rate = 10 mph
\n" ); document.write( "time = (1/3) / 10
\n" ); document.write( "time = 1/3 * (1/10)
\n" ); document.write( "time = 1/30 hour
\n" ); document.write( "time the stray ran = 0.0333 hours
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\n" ); document.write( "m.ananth@hotmail.ca
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