document.write( "Question 381287: 2x^2-3x=-5
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document.write( "Use quadratic formula to solve equation \n" );
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Algebra.Com's Answer #270432 by mananth(16946)![]() ![]() You can put this solution on YOUR website! 2x^2-3x=-5 \n" ); document.write( "+5 +5 \n" ); document.write( "2x^2-3x+5=0 \n" ); document.write( "... \n" ); document.write( "discriminant = -31\r \n" ); document.write( "\n" ); document.write( "... \n" ); document.write( "x1= ((-(-3)+sqrt(-31))/4 \n" ); document.write( "x1= 3/4 +sqrt(-31)/4 \n" ); document.write( "x1= 0.75 + 1.3919410907075053i \n" ); document.write( "... \n" ); document.write( "x2= ((-(-3)-sqrt(-31))/4 \n" ); document.write( "x2= 3/4 -sqrt(-31)/4 \n" ); document.write( "x2= 0.75 - 1.3919410907075053i \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |