document.write( "Question 381287: 2x^2-3x=-5
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Algebra.Com's Answer #270432 by mananth(16946)\"\" \"About 
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2x^2-3x=-5
\n" ); document.write( "+5 +5
\n" ); document.write( "2x^2-3x+5=0
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\n" ); document.write( "discriminant = -31\r
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\n" ); document.write( "x1= ((-(-3)+sqrt(-31))/4
\n" ); document.write( "x1= 3/4 +sqrt(-31)/4
\n" ); document.write( "x1= 0.75 + 1.3919410907075053i
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\n" ); document.write( "x2= ((-(-3)-sqrt(-31))/4
\n" ); document.write( "x2= 3/4 -sqrt(-31)/4
\n" ); document.write( "x2= 0.75 - 1.3919410907075053i
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\n" ); document.write( "m.ananth@hotmail.ca
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