document.write( "Question 41901: Hello!\r
\n" ); document.write( "\n" ); document.write( "Can somebody help please?\r
\n" ); document.write( "\n" ); document.write( "My question is:
\n" ); document.write( "Last time it was the kids birthdays I noticed that even though they were born only one year apart, when I squared their ages and then added the sum of the ages they would total 1105. How old are my kids?\r
\n" ); document.write( "\n" ); document.write( "Thanks. Your help and time are much appreciated.
\n" ); document.write( "marangeo \n" ); document.write( "
Algebra.Com's Answer #27042 by fractalier(6550)\"\" \"About 
You can put this solution on YOUR website!
Okay let their ages be x and x+1, since they are a year apart. Then we have
\n" ); document.write( "x^2 + (x+1)^2 + x + x+1 = 1105
\n" ); document.write( "Now solve this...
\n" ); document.write( "x^2 + x^2 + 2x + 1 + x + x + 1 = 1105
\n" ); document.write( "2x^2 + 4x + 2 = 1105
\n" ); document.write( "2x^2 + 4x - 1103 = 0
\n" ); document.write( "This is not factorable, so we use the quadratic formula to get
\n" ); document.write( "x = (-4 ± sqrt(16 + 8824)) / 4
\n" ); document.write( "x = (-4 ± sqrt(8840)) / 4
\n" ); document.write( "x = (-4 ± 2*sqrt(2210)) / 4
\n" ); document.write( "x = (-2 ± sqrt(2210)) / 2
\n" ); document.write( "x is about 22.5 years old
\n" ); document.write( "x+1 is about 23.5 years old
\n" ); document.write( "I have a feeling there is something wrong with the problem... \n" ); document.write( "
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