document.write( "Question 381215: 3x^2+5x-2 \n" ); document.write( "
Algebra.Com's Answer #270413 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Do you want to factor this? If so, then...\r
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"3x%5E2%2B5x-2\", we can see that the first coefficient is \"3\", the second coefficient is \"5\", and the last term is \"-2\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"3\" by the last term \"-2\" to get \"%283%29%28-2%29=-6\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"-6\" (the previous product) and add to the second coefficient \"5\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"-6\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"-6\":\r
\n" ); document.write( "\n" ); document.write( "1,2,3,6\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-6\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"-6\".\r
\n" ); document.write( "\n" ); document.write( "1*(-6) = -6
\n" ); document.write( "2*(-3) = -6
\n" ); document.write( "(-1)*(6) = -6
\n" ); document.write( "(-2)*(3) = -6\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"5\":\r
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First NumberSecond NumberSum
1-61+(-6)=-5
2-32+(-3)=-1
-16-1+6=5
-23-2+3=1
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"-1\" and \"6\" add to \"5\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"-1\" and \"6\" both multiply to \"-6\" and add to \"5\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"5x\" with \"-x%2B6x\". Remember, \"-1\" and \"6\" add to \"5\". So this shows us that \"-x%2B6x=5x\".\r
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\n" ); document.write( "\n" ); document.write( "\"3x%5E2%2Bhighlight%28-x%2B6x%29-2\" Replace the second term \"5x\" with \"-x%2B6x\".\r
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\n" ); document.write( "\n" ); document.write( "\"%283x%5E2-x%29%2B%286x-2%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"x%283x-1%29%2B%286x-2%29\" Factor out the GCF \"x\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"x%283x-1%29%2B2%283x-1%29\" Factor out \"2\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B2%29%283x-1%29\" Combine like terms. Or factor out the common term \"3x-1\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"3x%5E2%2B5x-2\" factors to \"%28x%2B2%29%283x-1%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"3x%5E2%2B5x-2=%28x%2B2%29%283x-1%29\".\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by expanding \"%28x%2B2%29%283x-1%29\" to get \"3x%5E2%2B5x-2\" or by graphing the original expression and the answer (the two graphs should be identical).\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, feel free to check out my tutoring website\r
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\n" ); document.write( "\n" ); document.write( "Jim
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