document.write( "Question 381141: The question wants you to find the complex zeros and factor the polynomial in standard form: F(X) = x^3 - 1. \n" ); document.write( "
Algebra.Com's Answer #270408 by neatmath(302)\"\" \"About 
You can put this solution on YOUR website!

We can easily see that \"f%28x%29=x%5E3-1\" is the difference of two cubes!
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=x%5E3-1\"
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29=%28x-1%29%28x%5E2%2Bx%2B1%29\"
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\n" ); document.write( "\n" ); document.write( "\"0=%28x-1%29%28x%5E2%2Bx%2B1%29\" set f(x) equal to zero, so we have
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\n" ); document.write( "\n" ); document.write( "\"%28x-1%29=0\" or \"%28x%5E2%2Bx%2B1%29=0\"
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\n" ); document.write( "\n" ); document.write( "\"x-1=0\"
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\n" ); document.write( "\n" ); document.write( "\"x=1\" or
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2Bx%2B1%29=0\"
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\n" ); document.write( "\n" ); document.write( "This will involve imaginary numbers because there are NO real numbers which satisfy this equation, but we can use the quadratic formula to find the complex solutions involving imaginary numbers:
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B1x%2B1+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%281%29%5E2-4%2A1%2A1=-3\".
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\n" ); document.write( " The discriminant -3 is less than zero. That means that there are no solutions among real numbers.

\n" ); document.write( " If you are a student of advanced school algebra and are aware about imaginary numbers, read on.

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\n" ); document.write( " In the field of imaginary numbers, the square root of -3 is + or - \"sqrt%28+3%29+=+1.73205080756888\".
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\n" ); document.write( " The solution is
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\n" ); document.write( " Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B1%2Ax%2B1+%29\"
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