document.write( "Question 41909: A triangular sheet of paper is 28 square inches, one side of the triangle is 2 inches more than 3 times the length of the altitudeto that side. Find the length of that side and the altitude to the side. please i donot know what formula to use of how to solve. this is not form the texbook. \n" ); document.write( "
Algebra.Com's Answer #27039 by venugopalramana(3286) You can put this solution on YOUR website! A triangular sheet of paper is 28 square inches, \n" ); document.write( "AREA=A=28=0.5*B*H WHERE B IS BASE AND H IS ALTITUDE. \n" ); document.write( " one side of the triangle is 2 inches more than 3 times the length of the altitudeto that side. \n" ); document.write( "3 TIMES ALTITUDE=3H \n" ); document.write( "2 MORE =3H+2=B \n" ); document.write( "AREA =A=28=0.5*(3H+2)H=1.5H^2+H..MULTIPLYING WITH 2 ..WE GET \n" ); document.write( "3H^2+2H=56 \n" ); document.write( "3H^2+2H-56=0 \n" ); document.write( "3H^2+14H-12H-56=0 \n" ); document.write( "H(3H+14)-4(3H+14)=0 \n" ); document.write( "(H-4)(3H+14)=0 \n" ); document.write( "H-4=0...THAT IS H=4...3H+14=0..LEADS TO NEGATIVE VALUES..SO NOT CONSIDERED. \n" ); document.write( "B=3H+2=3*4+2=14 \n" ); document.write( " Find the length of that side and the altitude to the side. please i donoknow what formula to use of how to solve. this is not form the texbook. \n" ); document.write( " \n" ); document.write( " |