document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=381140>Question 381140</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The outside dimensions of a picture frame are 3 feet by 29 inches.  If its inside dimensions are 1 2/3 feet by 22 inches, what is the area of the frame?\r<BR>\n" );
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document.write( "I've tried to do length times width on both sizes but the answer is a multiple choice and none of the answers I've come up with are a choice.  Here's what I've tried...outside--  36 inches x 29 inches= 1044 inches or 87 feet<BR>\n" );
document.write( "             inside-- 20 inches x 22 inches= 440 inches or 36.66 feet<BR>\n" );
document.write( "answer choices are A) 137.33 ft2    B) 616 in2   C) 144.67 ft2    D) 604 in2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #270387 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=270387\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> you actually have found the answer , except for the final step\r<BR>\n" );
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document.write( "the inches of AREA that you have calculated are actually square inches (or in^2)\r<BR>\n" );
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document.write( "if you take the difference of your two calculations , you'll see the answer\r<BR>\n" );
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document.write( "FYI ... 144 in^2 = 1 ft^2 </SPAN>\n" );
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