document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=381022>Question 381022</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Set up a equation and solve the problem: One positive number is 4 larger than another number and the sum of their square is 136. Find the numbers? I am having a hard time with this one. I hope you can help. Thanks  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #270370 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=270370\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=first positive number<BR>\n" );
document.write( "Then x+4=the other positive number<BR>\n" );
document.write( "And we are told that:<BR>\n" );
document.write( "x^2+(x+4)^2=136 simplify<BR>\n" );
document.write( "x^2+x^2+8x+16=136 subtract 136 from each side and collect like terms<BR>\n" );
document.write( "2x^2+8x-120=0  divide each term by 2<BR>\n" );
document.write( "x^2+4x-60=0----quadratic in standard form and it can be factored:<BR>\n" );
document.write( "(x+10)(x-6)=0<BR>\n" );
document.write( "x=-10------no good!  Problem specifies positive numbers<BR>\n" );
document.write( "x=6----The first positive number<BR>\n" );
document.write( "6+4=10 the second positive number<BR>\n" );
document.write( "CK\r<BR>\n" );
document.write( "\n" );
document.write( "6^2 + 10^2=136<BR>\n" );
document.write( "136=136\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps---ptaylor </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );