document.write( "Question 381014: Train A is 8 mph slower than train B. Train A travels 230 miles in the same time that train B travels in 270 miles. What is the speed of both trains? \n" ); document.write( "
Algebra.Com's Answer #270369 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r \n" ); document.write( "Let r=train B's speed \n" ); document.write( "Then r-8=train A's speed \n" ); document.write( "230/(r-8) = time it takes train A to travel 230 mi \n" ); document.write( "270/r=time it takes train B to travel 270 mi \n" ); document.write( "Now we are told that the above two times are equal, so: \n" ); document.write( "230/(r-8)=270/r multiply each term by r(r-8) \n" ); document.write( "230r=270(r-8) \n" ); document.write( "230r=270r-2160 subtract 270r from each side \n" ); document.write( "230r-270r=-2160 \n" ); document.write( "-40r=-2160 \n" ); document.write( "r=54 mph---train B's speed \n" ); document.write( "54-8=46 mph---train A's speed\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "230/46 = 270/54 \n" ); document.write( "5=5\r \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " \n" ); document.write( " |