document.write( "Question 380916: write the expression (log base of b)(2y+5)-4(log base of b)(y+3) as a single
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Algebra.Com's Answer #270329 by Theo(13342)\"\" \"About 
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that expression would be shown as:\r
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\n" ); document.write( "\n" ); document.write( "log(b,(2y+5)) - 4*log(b,(y+3))\r
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\n" ); document.write( "\n" ); document.write( "in general x * log(y) = log(y^x)\r
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\n" ); document.write( "\n" ); document.write( "your expression becomes:\r
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\n" ); document.write( "\n" ); document.write( "log(b,(2y+5)) - log(b,((y+3)^4))\r
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\n" ); document.write( "\n" ); document.write( "in general log(x) - log(y) = log(x/y)\r
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\n" ); document.write( "\n" ); document.write( "your expression becomes:\r
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\n" ); document.write( "\n" ); document.write( "log(b,((2y+5)/(y+3)^4))\r
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\n" ); document.write( "\n" ); document.write( "to show you how this works, we will let b = 10 because your calculator can do logs to the base of 10 (usually called the LOG function).\r
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\n" ); document.write( "\n" ); document.write( "we will let y = 5 (chosen at random small enough to calculate easily).\r
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\n" ); document.write( "\n" ); document.write( "your original expression becomes:\r
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\n" ); document.write( "\n" ); document.write( "log(2y+5) - 4*log(y+3)\r
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\n" ); document.write( "\n" ); document.write( "the base of 10 is implied.\r
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\n" ); document.write( "\n" ); document.write( "substituting 5 for y, we get:\r
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\n" ); document.write( "\n" ); document.write( "log(2*5+5) - 4*log(5+3) which becomes:\r
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\n" ); document.write( "\n" ); document.write( "log(15) - 4*log(8) which becomes -2.436268689\r
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\n" ); document.write( "\n" ); document.write( "looking at our final expression of:\r
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\n" ); document.write( "\n" ); document.write( "log(b,(2y+5)/(y+3)^4), we get:\r
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\n" ); document.write( "\n" ); document.write( "log((2y+5)/(y+3)^4).\r
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\n" ); document.write( "\n" ); document.write( "the base of 10 is implied.\r
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\n" ); document.write( "\n" ); document.write( "substituting 5 for y, we get:\r
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\n" ); document.write( "\n" ); document.write( "log(15/8^4) which becomes log(15/4096).\r
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\n" ); document.write( "\n" ); document.write( "using our calculator, we get log(15/4096) = log(.003662109) which equals -2.436268689\r
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\n" ); document.write( "\n" ); document.write( "we get the same answer either way, so the translation is good, and the answer to your question is:\r
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\n" ); document.write( "\n" ); document.write( "log(b,2y+5) - 4*log(b,y+3) = log(b,(2y+5)/(y+3)^4) which looks like:\r
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