document.write( "Question 380915: Write the expression log2(6x/y) as a sum and/ or difference of logarithms \n" ); document.write( "
Algebra.Com's Answer #270327 by Theo(13342)![]() ![]() You can put this solution on YOUR website! log(2,6x/y) is equal to the log of 6x/y to the base of 2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it means the same as what you wrote as log2(6x/y).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the notation, however, is more in line with the way the algebra.com formula generators work.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "using the algebra.com formula generator, log(2,6x/y) will show up as \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "All you do is put 3 { in front of it and 3 } behind it.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in general, log(x/y) = log(x) - log(y)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your equation becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log(2,6x/y) = log(2,6x) - log(2,y)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in general, log (x*y) = log(x) + log(y)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your equation becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log(2,6x/y) = log(2,6) + log(2,x) - log(y)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the concept is the same regardless of the base.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if the base were 10, then it would be shown as:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log(10,6x/y) = log(10,6) + log(10,x) - log(10,y)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to show you how it works, we'll use log to the base 10 because your calculator can handle that.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "also, log(10,x) is normally shown as log(x).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the base of 10 is implied.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let's take log(6*15/30)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this should be translated to log(6) + log(15) - log(30) which is the same treatment we provided above.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "using our calculator, we get log(6*15/30) = log(3) = .477121255\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "using our calculator again, we get log(6) + log(15) - log(30) = :\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".77815125 + 1.176091259 - 1.477121255 = .477121255\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "we get the same answer, as we should.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "same concepts works with any base, so the answer to your question is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log(2,6x/y) = log(2,6) + log(2,x) - log(2,y).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |