document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=380930>Question 380930</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive odd positive intergers such that 5 times the sum of all three is 66 more then the product of the first and second intergers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #270302 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=270302\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the integers be x,x+2,x+4<BR>\n" );
document.write( "...<BR>\n" );
document.write( "5(x+x+2+x+4)=x(x+2)+66<BR>\n" );
document.write( "5(3x+6)=x^2+2x+66<BR>\n" );
document.write( "15x+30=x^2+2x+66<BR>\n" );
document.write( "-15x <BR>\n" );
document.write( "30=x^2+2x-15x+66<BR>\n" );
document.write( "30=x^2-13x+66<BR>\n" );
document.write( "-30<BR>\n" );
document.write( "0=x^2-13x+36<BR>\n" );
document.write( "x^2-9x-4x+36=0<BR>\n" );
document.write( "x(x-9)-4(x-9)=0<BR>\n" );
document.write( "(x-9)(x-4)=0<BR>\n" );
document.write( "x= 9 OR 4.<BR>\n" );
document.write( "reject 4<BR>\n" );
document.write( "x= 9 <BR>\n" );
document.write( "the numbers are 9,11,13.\r<BR>\n" );
document.write( "\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );