document.write( "Question 380875: how to solve this equation using substitution method? with checking.
\n" ); document.write( "1/x + 1/y=0
\n" ); document.write( "2/x + 5/y=-6
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #270290 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
Use a substitution,
\n" ); document.write( "let $\"u=1%2Fx\"$ and $\"v=1%2Fy\"$ .
\n" ); document.write( "1. $\"u%2Bv=0\"$
\n" ); document.write( "2. $\"2u%2B5v=-6\"$
\n" ); document.write( "From eq. 1,
\n" ); document.write( " $\"u=-v\"$
\n" ); document.write( "Substitute into eq. 2,
\n" ); document.write( " $\"-2v%2B5v=-6\"$
\n" ); document.write( " $\"3v=-6\"$
\n" ); document.write( " $\"v=-2\"$
\n" ); document.write( " $\"1%2Fy=-2\"$
\n" ); document.write( " $\"highlight%28y=-1%2F2%29\"$
\n" ); document.write( "Then from eq. 1,
\n" ); document.write( " $\"u=-%28-2%29\"$
\n" ); document.write( " $\"u=2\"$
\n" ); document.write( " $\"1%2Fx=2\"$
\n" ); document.write( " $\"highlight%28x=1%2F2%29\"$
\n" ); document.write( " \n" ); document.write( "

\n" );