document.write( "Question 380874: I need help to find the x and y intercepts of these circles. Circle 1 (x+2)^2+(y+3)^2=4 and Circle 2 x^2+y^2-18x-2y+66=0.
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Algebra.Com's Answer #270283 by robertb(5830) $\"\"$ $\"About$

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Circle 1: Letting y = 0 to solve for the x-int, we get $\"+%28x%2B2%29%5E2+%2B+9=4\"$ . This equation has no solution, hence there are no x-intercepts.
\n" ); document.write( " Letting x = 0 to find the y-int, we get $\"4%2B%28y%2B3%29%5E2=4\"$ . The only solution is y =-3.Thus the y-intercept is (0,-3).\r
\n" ); document.write( "\n" ); document.write( "Circle 2: Let y = 0 to find the x-int. Then $\"x%5E2-18x%2B66=0\"$ . The solutions to this are $\"x+=+%2818+%2B-+sqrt%2860+%29%29%2F2+=+9+%2B-+sqrt%2815+%29\"$ . These are also the x-intercepts.
\n" ); document.write( "Let x = 0 to find the y-int. Then $\"y%5E2-2y%2B66=0\"$ . This equation has no real roots. Therefore there are no y-intercepts. \n" ); document.write( "

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