document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=380794>Question 380794</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve by factoring and using the principle of zero products:  2x^2-11x+15=0\r<BR>\n" );
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document.write( "I am not sure if I am doing this correctly.  My answer was x=5/2 and x=-3 but I do not feel confident in these.... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #270246 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=270246\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x^2-11x+15=0  factor<BR>\n" );
document.write( "(2x-5)(x-3)=0 set each factor equal to zero and solve each factor for \"x\"\r<BR>\n" );
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document.write( "2x-5=0<BR>\n" );
document.write( "2x=5<BR>\n" );
document.write( "x=5/2<BR>\n" );
document.write( "and<BR>\n" );
document.write( "x-3=0<BR>\n" );
document.write( "x=3<BR>\n" );
document.write( ".<BR>\n" );
document.write( "be sure to check by plugging each x back into the orignal equation.  see what happens when yopu plug either 3 or -3 back into the equation.  you are on the right track.  good job. </SPAN>\n" );
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