document.write( "Question 41895: Use the value of discriminant to determine the number and type of roots for the equation 2x^2-7x+9=0.\r
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Algebra.Com's Answer #27020 by psbhowmick(878)\"\" \"About 
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Comparing the given equation \"2x%5E2-7x%2B9=0\" with the standard quadratic equation \"ax%5E2%2Bbx%2Bc=0\" we find a = 2, b = -7, c = 9.\r
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\n" ); document.write( "\n" ); document.write( "The discriminant is \"D+=+b%5E2-4ac\".
\n" ); document.write( "Then if the coefficients i.e. a, b, c are real:
\n" ); document.write( "1) If D > 0, the roots are real but unequal.
\n" ); document.write( "2) If D = 0, the roots are real and equal.
\n" ); document.write( "3) If D < 0, the roots are imaginery and conjugate.\r
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\n" ); document.write( "\n" ); document.write( "Special case:
\n" ); document.write( "If D > 0, D is a perfect square and the coefficients are also rational then the roots are also rational.\r
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\n" ); document.write( "\n" ); document.write( "Here, \"D+=+%28-7%29%5E2+-+4%2A2%2A9\" = 49 - 72 = -23.
\n" ); document.write( "Hence, D < 0, also the coefficients are real and so the roots are imaginery and conjugate.\r
\n" ); document.write( "\n" ); document.write( "For a brief discussion on rational numbers you may see my lesson at
\n" ); document.write( "http://www.algebra.com/tutors/INTRODUCTION_TO_RATIONAL_AND_IRRATIONAL_NUMBERS.lesson?content_action=show_dev
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