document.write( "Question 380610: How much pure acid should be mixed with 6 gallons of a 10% acid solution in order to get a 90% acid solution? \n" ); document.write( "

Algebra.Com's Answer #270189 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "Let x represent the amount of the 100% pure acid solution
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document.write( "1.00x + .10*6gal = .90*(x + 6gal)
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document.write( "solving for x
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document.write( ".10x = .80*6gal
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document.write( "x = 48 gal of pure acid needed.\r
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document.write( "CHECKING our Answer
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document.write( "48gal + .6gal = 48.6gal = .9*54gal = 48.6gal \n" );
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