document.write( "Question 380613: How much pure acid should be mixed with 2 gallons of a 40% acid solution in order to get a 80% acid solution? \n" ); document.write( "

Algebra.Com's Answer #270185 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "Let x represent the amount of the 100% pure acid solution
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document.write( "1.00x + .40*2gal = .80*(x + 2gal)
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document.write( "solving for x
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document.write( ".20x = .40*2gal
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document.write( "x = 4 gal of pure acid needed.\r
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document.write( "CHECKING our Answer
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document.write( "4 + .8 = 4.8 = .8*6 \n" );
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