document.write( "Question 380579: Good morning! \r
\n" ); document.write( "\n" ); document.write( "I have to find the inverse of the function: f(x)= 4x+1/3. \r
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\n" ); document.write( "\n" ); document.write( "Denise
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Algebra.Com's Answer #270164 by Jk22(389)\"\" \"About 
You can put this solution on YOUR website!
Let write the inverse g(x)=f^(-1)(x), then we should have : \r
\n" ); document.write( "\n" ); document.write( "f(g(x)) = x = 4g(x)+1/3 => g(x) = (x-1/3)/4
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\n" ); document.write( "we can see that g(f(x)) = (f(x)-1/3)/4 = (4x+1/3-1/3)/4 = x
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\n" ); document.write( "Note : the functional inverse is not the inverse in the real numbers, which were denoted f(x)^(-1) = 1/(4x+1/3)
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