document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41903>Question 41903</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x-6y=11<BR>\n" );
document.write( "3y-3x=12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #27015 by </B><A HREF=/tutors/aboutme.mpl?userid=psbhowmick><B>psbhowmick(878)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=psbhowmick><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=psbhowmick><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=27015\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x - 6y = 11___________(1)\r<BR>\n" );
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document.write( "3y - 3x = 12 <BR>\n" );
document.write( "or y - x = 12/3 <BR>\n" );
document.write( "or y - x = 4___________(2)\r<BR>\n" );
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document.write( "Adding (1) and (2) we can eliminate 'x'.<BR>\n" );
document.write( "Thus we have,<BR>\n" );
document.write( "y - 6y = 4 + 11<BR>\n" );
document.write( "or -5y = 15<BR>\n" );
document.write( "or y = -15/5 = -3<BR>\n" );
document.write( "Substituting y = -3 in (2) we have<BR>\n" );
document.write( "-3 - x = 4<BR>\n" );
document.write( "or x = -3 -4 = -7\r<BR>\n" );
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document.write( "Answer: x = -7, y = -3 </SPAN>\n" );
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