document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=380543>Question 380543</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help in trying to rewrite this expression as a single logarithm.\r<BR>\n" );
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document.write( "Log(Q^5) + Log(Q^3) - Log(Q)\r<BR>\n" );
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document.write( "Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #270145 by </B><A HREF=/tutors/aboutme.mpl?userid=rfadrogane><B>rfadrogane(214)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfadrogane><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rfadrogane><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=270145\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Log(Q^5) + Log(Q^3) - Log(Q)\r<BR>\n" );
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document.write( "Sol'n:<BR>\n" );
document.write( " recall: log A + log B = log AB<BR>\n" );
document.write( "         log A - log B = log (A/B)<BR>\n" );
document.write( "thus,<BR>\n" );
document.write( " = log(Q^5) + log(Q^3) - log(Q)<BR>\n" );
document.write( " = log (Q^5/Q^3)- log Q<BR>\n" );
document.write( " = log (Q^2)- log Q<BR>\n" );
document.write( " = log (Q^2/Q)<BR>\n" );
document.write( " = log Q ----answer </SPAN>\n" );
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