document.write( "Question 380397: I have 30 coins, all nickels, dimes, and quarters, worth $4.60. There are two more dimes than quarters. How many of each kind of coin do I have. \n" ); document.write( "
Algebra.Com's Answer #270073 by mananth(16946)![]() ![]() You can put this solution on YOUR website! I have 30 coins, all nickels, dimes, and quarters, worth $4.60. There are two more dimes than quarters. How many of each kind of coin do I have. \n" ); document.write( ".. \n" ); document.write( "let quarters be x \n" ); document.write( "dimes = x+2 \n" ); document.write( "... \n" ); document.write( "dimes + quarters = x+x+2=2x+2 \n" ); document.write( "... \n" ); document.write( "nickels = 30-(2x+2) \n" ); document.write( "... \n" ); document.write( "5(30-(2x+2))+10(x+2)+25x=460 \n" ); document.write( "5(30-2x-2)+10x+20+25x=460 \n" ); document.write( "150-10x-10+10x+20+25x=460 \n" ); document.write( "160+25x=460 \n" ); document.write( "-160 \n" ); document.write( "25x=460-160 \n" ); document.write( "25x=300 \n" ); document.write( "/25 \n" ); document.write( "x=300/25 \n" ); document.write( "x=12 ---- quarters \n" ); document.write( "x+2= 12+2=14 dimes \n" ); document.write( "30-(2x+2)=4 nickels \n" ); document.write( "... \n" ); document.write( "check \n" ); document.write( "4*5+14*10+12*25=20+140+300=460\r \n" ); document.write( "\n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |