document.write( "Question 380474: The perimeter of a rectangle is 50m. If the width was doubled and the length was increased by 20m, the perimeter would be 100m. What are the length and width of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #270070 by mananth(16946)\"\" \"About 
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The perimeter of a rectangle is 50m. If the width was doubled and the length was increased by 20m, the perimeter would be 100m. What are the length and width of the rectangle?
\n" ); document.write( "...
\n" ); document.write( "let width be w
\n" ); document.write( "length = l
\n" ); document.write( "..
\n" ); document.write( "Area A = l*w=50 m^2
\n" ); document.write( "l= 50/w
\n" ); document.write( "...
\n" ); document.write( "second rectangle
\n" ); document.write( "width = 2w
\n" ); document.write( "length = l+20
\n" ); document.write( "Perimeter of second rectangle =2*(2w+(l+20))
\n" ); document.write( "P=2(2w+l+20)
\n" ); document.write( "P=4w+2l+40
\n" ); document.write( "plug the value of l above
\n" ); document.write( "P=4w+2(50/w)+40
\n" ); document.write( "100=4w+100/w+40
\n" ); document.write( "multiply by w
\n" ); document.write( "100w=4w^2+100+40w
\n" ); document.write( "re write
\n" ); document.write( "4w^2-100w+40w+100=0
\n" ); document.write( "4w^2-60w+100=0
\n" ); document.write( "/4
\n" ); document.write( "w^2-15w+25=0
\n" ); document.write( "find the roots w1,w2 using quadratic formula
\n" ); document.write( "..
\n" ); document.write( "discriminant = 125
\n" ); document.write( "w1=((15+sqrt(125))/2)
\n" ); document.write( "w1=13.1 meters ... the width
\n" ); document.write( "w2 will be negative so ignore
\n" ); document.write( "length = 50/13.1
\n" ); document.write( "length = 3.82 meters
\n" ); document.write( "...
\n" ); document.write( "CHECK perimeter of second rectangle
\n" ); document.write( "plug w & l
\n" ); document.write( "2*(2*13.1+((3.82+20))=100
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\n" ); document.write( "m.ananth@hotmail.ca
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