document.write( "Question 41865This question is from textbook
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document.write( ": A passenger train can travel 325 mi in the same time a freight train takes to travel 200 mi. If the speed of the passenger train is 25 mi/h faster that the speed of the freight train, finfd the speed of each.\r
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document.write( "Thanks! \n" );
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Algebra.Com's Answer #27001 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! Let x be the speed of friehgt train \n" ); document.write( "Let x+25 be the speed of passenger train \n" ); document.write( "Equation: \n" ); document.write( "325(x)=200(x+25) \n" ); document.write( "SOlve from there \n" ); document.write( "Paul. \n" ); document.write( " |