document.write( "Question 380432: A plane traveled a distance of 800 miles and returned the same distance. If the rate returning is 40 miles per hour faster than the rate going, and if the total flight took 8 hours, how fast did the plane travel on the return trip? \n" ); document.write( "
Algebra.Com's Answer #269993 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Distance = 800 miles . speed going = x mph \n" ); document.write( "distance = 800 miles : speed = x+40 mph. \n" ); document.write( "... \n" ); document.write( "time going +time returning=8 \n" ); document.write( ".. \n" ); document.write( "t=d/r \n" ); document.write( "800/x+800/(x+40 )= 8 \n" ); document.write( ".. \n" ); document.write( "lcd = x(x+40) \n" ); document.write( "800(x+40)+800x /x(x+40)=8 \n" ); document.write( "800x+32000+800x=8x^2+320x \n" ); document.write( "8x^2-1600x+320x-32000=0 \n" ); document.write( "8x^2-1280x-32000=0 \n" ); document.write( "/8 \n" ); document.write( "x^2-160x-4000=0 \n" ); document.write( ".. \n" ); document.write( "find the roots x1,x2 using quadratic formula \n" ); document.write( "discriminant = 41600 \n" ); document.write( "x1=((160+sqrt(41600))/2 \n" ); document.write( "x1= 181.98 = 182 mph \n" ); document.write( "x2 is negative so reject. \n" ); document.write( "return trip speed = x+40 = 182 +40 = 222 mph \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |