document.write( "Question 41822: With the current, a motorboat travels 60 mi in 3 h. Against the current, it takes 2 h longer to travel 60 mi. Find the rate of the current. \n" ); document.write( "
Algebra.Com's Answer #26999 by Paul(988)\"\" \"About 
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Let y be the speed of the boat
\n" ); document.write( "Let x be the speed of the current
\n" ); document.write( "2 hours longer = 5 hours total
\n" ); document.write( "FIRST EQUATION:
\n" ); document.write( "3x+3y=60
\n" ); document.write( "y=20-x (Subsitution)\r
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\n" ); document.write( "\n" ); document.write( "SECOND EQUATION:
\n" ); document.write( "5x-5y=60
\n" ); document.write( "y=12+x
\n" ); document.write( "SUBSITUTE
\n" ); document.write( "20-x=12+x
\n" ); document.write( "2x=8
\n" ); document.write( "x=4
\n" ); document.write( "y=20-4
\n" ); document.write( "y=16
\n" ); document.write( "Hence, the speed of the boat is 16mph and the speed of the current 4mph.
\n" ); document.write( "Paul.
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