document.write( "Question 41822: With the current, a motorboat travels 60 mi in 3 h. Against the current, it takes 2 h longer to travel 60 mi. Find the rate of the current. \n" ); document.write( "
Algebra.Com's Answer #26999 by Paul(988)![]() ![]() ![]() You can put this solution on YOUR website! Let y be the speed of the boat \n" ); document.write( "Let x be the speed of the current \n" ); document.write( "2 hours longer = 5 hours total \n" ); document.write( "FIRST EQUATION: \n" ); document.write( "3x+3y=60 \n" ); document.write( "y=20-x (Subsitution)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "SECOND EQUATION: \n" ); document.write( "5x-5y=60 \n" ); document.write( "y=12+x \n" ); document.write( "SUBSITUTE \n" ); document.write( "20-x=12+x \n" ); document.write( "2x=8 \n" ); document.write( "x=4 \n" ); document.write( "y=20-4 \n" ); document.write( "y=16 \n" ); document.write( "Hence, the speed of the boat is 16mph and the speed of the current 4mph. \n" ); document.write( "Paul. \n" ); document.write( " |