document.write( "Question 380177: Find the equation of the tangent and normal to the conic 4x^2 + 9y^2 = 40 at point (1,-2). \n" ); document.write( "
Algebra.Com's Answer #269955 by richard1234(7193)\"\" \"About 
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Given the ellipse \"4x%5E2+%2B+9y%5E2+=+40\", if we differentiate with respect to x, we have\r
\n" ); document.write( "\n" ); document.write( "\"8x+%2B+18y%28dy%2Fdx%29+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"dy%2Fdx+=+-8+x%2F18+y+=+-4+x%2F9+y\"\r
\n" ); document.write( "\n" ); document.write( "Therefore the slope at (1, -2) is \"%28-4%2A1%29%2F%289%2A-2%29+=+2%2F9\"\r
\n" ); document.write( "\n" ); document.write( "Given slope 2/9 and a point (1, -2) we can easily find the y-intercept:\r
\n" ); document.write( "\n" ); document.write( "\"-2+=+%282%2F9%29%281%29+%2B+b\"
\n" ); document.write( "\"b+=+-20%2F9\"\r
\n" ); document.write( "\n" ); document.write( "Thus the equation of the line tangent to the ellipse at (1, -2) is \"y+=+%282%2F9%29x+-+20%2F9\"
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