document.write( "Question 380363: Find the zeros of $\"f%28x%29+=+x%5E2+%2B+6%2Ax+-+7\"$ . The zeros of f(x) are \n" ); document.write( "

Algebra.Com's Answer #269938 by kingme18(98) $\"\"$ $\"About$

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The zeros of a function are the values of x that would make the function equal 0.\r
\n" ); document.write( "\n" ); document.write( "The easiest way to find the zeros in your function is to factor it. 7 * -1 = -7 and 7 + -1 = 6, so this will factor as f(x) = (x + 7)(x - 1)\r
\n" ); document.write( "\n" ); document.write( "The zeros can be found by setting this equal to 0: (x + 7)(x - 1) = 0\r
\n" ); document.write( "\n" ); document.write( "When two numbers multiply to 0, one of them must be 0. Thus, either x + 7 = 0 or x - 1 = 0. Solve each for x, and x = -7 or x = 1. Those are your zeros. You can check by plugging each into the original equation for x; you'll end up with 0 for each! \n" ); document.write( "

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