document.write( "Question 380346: -x^2+12x=36 by graphing the x intercept is? \n" ); document.write( "

Algebra.Com's Answer #269913 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "graphing 
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document.write( "-x^2+12x=36
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document.write( " x^2 -12x +36 = 0  
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document.write( " factoring
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document.write( " (x-6)(x-6) = 0 Note:SUM of the inner product(-6x) and the outer product(-6x) = -12x
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document.write( " (x-6)= 0
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document.write( " (x-6) = 0
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document.write( "x = 6  Pt(6,0) the x intercept
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document.write( " x^2 -12x +36 = (x-6)^2  
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document.write( "the vertex form of a parabola,  where(h,k) is the vertex
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document.write( "here, the vertex is at Pt(6,0) a = 1 (a is positive, graph opens upward)
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