document.write( "Question 380164: Mary starts jogging from her home to the park at the speed of 4kph. Half an hr later, Fred follows running at a speed of 9 kph. How long before Fred overtakes Mary? \n" ); document.write( "
Algebra.Com's Answer #269906 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Mary starts jogging from her home to the park at the speed of 4kph. \n" ); document.write( " Half an hr later, Fred follows running at a speed of 9 kph. \n" ); document.write( " How long before Fred overtakes Mary? \n" ); document.write( ": \n" ); document.write( "Let t = time required for F to catch M \n" ); document.write( ": \n" ); document.write( "When this happens, they will have traveled the same distance \n" ); document.write( ": \n" ); document.write( "convert 30 min to .5 hrs \n" ); document.write( ": \n" ); document.write( "Write a distance equation; dist = speed * time \n" ); document.write( "; \n" ); document.write( "F's dist = M's dist \n" ); document.write( "9t = 4(t+.5) \n" ); document.write( "9t = 4t + 2 \n" ); document.write( "9t - 4t = 2 \n" ); document.write( "5t = 2 \n" ); document.write( "t = \n" ); document.write( "or \n" ); document.write( ".4 * 60 = 24 minutes \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution by finding the dist each traveled, should be equal: \n" ); document.write( "9 * .4 = 3.6 mi \n" ); document.write( "4 *(.4 + .5) = 3.6 mi; confirms our solution of t = .4 \n" ); document.write( " \n" ); document.write( " |