document.write( "Question 380300: Write the slope-intercept form of an equation for a line that passes through (-1, 0) and is perpendicular to the graph of 3x – 5y = 20. \n" ); document.write( "

Algebra.Com's Answer #269890 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "Line perpendicular to the graph of 
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document.write( "3x – 5y = 20  Solving for y to put into the slope-intercept form
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document.write( "3x - 20 = 5y
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document.write( "(2/5)x - 4 = y
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document.write( "Note: the standard slope-intercept form for an equation of a line is y = mx + b  
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document.write( "where m is the slope and b the y-intercept.  
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document.write( "y = (2/5)x - 4 slope of this line is (2/5), line perpendicular to it m = -(5/2}
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document.write( "New line:
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document.write( " y  = (-5/2)x + b  using ordered pair Pt(-1,0) to solve for b
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document.write( " 0  = -5/2(-1) + b
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document.write( " -5/2 = b
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document.write( "y = (-5/2)x - 5/2
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