document.write( "Question 380283: If Denny who walks 60 meters per minute has already walked 1800 meters, how many minutes will it take for John who cycles 210 per minute to catch up with Denny by bike? \n" ); document.write( "

Algebra.Com's Answer #269876 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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If Denny who walks 60 meters per minute has already walked 1800 meters,
\n" ); document.write( " how many minutes will it take for John who cycles 210 per minute to catch
\n" ); document.write( " up with Denny by bike?
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\n" ); document.write( "Let t = no. of minutes for J to catch D
\n" ); document.write( ":
\n" ); document.write( "Find out how many minutes that D has walked already
\n" ); document.write( " $\"1800%2F60\"$ = 30 minutes
\n" ); document.write( ":
\n" ); document.write( "When J catches D the will have traveled the same dist;
\n" ); document.write( "Write a dist equation; dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "J's dist = D's dist
\n" ); document.write( "210t = 60(t+30)
\n" ); document.write( "210t = 60t + 1800
\n" ); document.write( "210t - 60t = 1800
\n" ); document.write( "150t = 1800
\n" ); document.write( "t = $\"1800%2F150\"$
\n" ); document.write( "t = 12 minutes for J to catch D
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\n" ); document.write( ":
\n" ); document.write( "Confirm this by finding the distance of each, should be equal:
\n" ); document.write( "210*12 = 2520 meters
\n" ); document.write( "60(12+30) = 2520 meters also \n" ); document.write( "

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