document.write( "Question 378767: in a geometric sequence the fourth term is 8 and the tenth term is 512. if common ratio is negative, find the first three terms.
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Algebra.Com's Answer #269872 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi,
\n" ); document.write( "For a Geometric Sequence with common ratio= r \"a%5Bn%5D+=+a%5B1%5D%2Ar%5E%28n-1%29\" Question States
\n" ); document.write( "\"a%5B4%5D+=+a%5B1%5D%2Ar%5E%284-1%29=8\"
\n" ); document.write( "\"r%5E3+=+8%2Fa%5B1%5D\"
\n" ); document.write( "\"a%5B10%5D+=+a%5B1%5D%2Ar%5E%2810-1%29=+a%5B1%5D%2Ar%5E%289%29=++512\"
\n" ); document.write( "\"%28a%5B1%5D%2Fa%5B1%5D%5E3%29%2A8%5E3=+512\"
\n" ); document.write( "\"+a%5B1%5D%5E2=+1+\"
\n" ); document.write( "\"a%5B1%5D+=+-1\" as the and common ratio is given as negative \"r%5E3+=+8\" r= -2\r
\n" ); document.write( "\n" ); document.write( "CHECKING our answer by reviewing the first 10 terms of this sequence:
\n" ); document.write( " -1, 2, -4, 8, -16, 32, -64, 128, -256, 512 \n" ); document.write( "
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