document.write( "Question 380207: Frank has half as many again as sally who has half again as many again as mary. Altogether they have 209.
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document.write( "how many has each? \n" );
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Algebra.Com's Answer #269846 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Frank has half as many again as sally who has half again as many again as mary. Altogether they have 209. \n" ); document.write( "how many has each? \n" ); document.write( "--- \n" ); document.write( "Let Mary have \"x\" \n" ); document.write( "Then Sally has \"(3/2)x\" \n" ); document.write( "And Frank has (3/2)(3/2 x) = (9/4)x \n" ); document.write( "----------------------------------------- \n" ); document.write( "Equation: \n" ); document.write( "x + (3/2)x + (9/4)x = 209 \n" ); document.write( "4x + 6x + 9x = 4*209 \n" ); document.write( "19x = 4*209 \n" ); document.write( "x = 44 \n" ); document.write( "(3/2)x = 66 \n" ); document.write( "(9/4)x = 99 \n" ); document.write( "================== \n" ); document.write( "cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============== \n" ); document.write( " \n" ); document.write( " |