document.write( "Question 380207: Frank has half as many again as sally who has half again as many again as mary. Altogether they have 209.
\n" ); document.write( "how many has each?
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Algebra.Com's Answer #269846 by stanbon(75887)\"\" \"About 
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Frank has half as many again as sally who has half again as many again as mary. Altogether they have 209.
\n" ); document.write( "how many has each?
\n" ); document.write( "---
\n" ); document.write( "Let Mary have \"x\"
\n" ); document.write( "Then Sally has \"(3/2)x\"
\n" ); document.write( "And Frank has (3/2)(3/2 x) = (9/4)x
\n" ); document.write( "-----------------------------------------
\n" ); document.write( "Equation:
\n" ); document.write( "x + (3/2)x + (9/4)x = 209
\n" ); document.write( "4x + 6x + 9x = 4*209
\n" ); document.write( "19x = 4*209
\n" ); document.write( "x = 44
\n" ); document.write( "(3/2)x = 66
\n" ); document.write( "(9/4)x = 99
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\n" ); document.write( "cheers,
\n" ); document.write( "Stan H.
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