document.write( "Question 380163: Every morning, Don Miguel exercises by walking a certain distance at an average of 4 kph, rests for 20 min. and rides back along the same road on his chauffer-driven limousine at an average speed of 60 kph. If the total time of travel is one hr. and 15 min. how far does he walk? \n" ); document.write( "
Algebra.Com's Answer #269824 by mananth(16946)\"\" \"About 
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let the distance he walks be x
\n" ); document.write( "speed of walking = 4 kph
\n" ); document.write( "time walking = x/4 hours
\n" ); document.write( "..
\n" ); document.write( "t=d/r
\n" ); document.write( "d=4x
\n" ); document.write( "r=60 kph
\n" ); document.write( "time driven = x/60 hours
\n" ); document.write( "...
\n" ); document.write( "rest = 20/60 = 1/3 hours
\n" ); document.write( "..
\n" ); document.write( "time walk + time drive + rest = 1 h 15 mins (= 1 1/4 hour = 5/4 hours)
\n" ); document.write( "...\r
\n" ); document.write( "\n" ); document.write( "x/4 + x/60 + 1/3 = 5/4
\n" ); document.write( "- 1/3
\n" ); document.write( "x/4 +x/60 = 5/4-1/3
\n" ); document.write( "x/4+x/60 = (15-4)/12
\n" ); document.write( "x/4+x/60 = (11)/12
\n" ); document.write( "LCD = 60
\n" ); document.write( "(15x+x)/60 = 11/12
\n" ); document.write( "cross multiply
\n" ); document.write( "12*16x=660
\n" ); document.write( "192x=660
\n" ); document.write( "/192
\n" ); document.write( "x=660/192
\n" ); document.write( "x= 3.44 km the distance he walked.
\n" ); document.write( "...
\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "
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