document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=380158>Question 380158</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Gerald and John agreed to start from the same point and go in opposite directions every morning for a jog. If Gerald runs at a speed of 3km/hr ans John has a speed of 4km/hr,in how many hrs. will they be 14 km apart? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #269817 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=269817\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Gerald runs at a speed of 3km/hr <BR>\n" );
document.write( "John has a speed of 4km/hr,<BR>\n" );
document.write( "in how many hrs. will they be 14 km apart<BR>\n" );
document.write( "..<BR>\n" );
document.write( "they are running in opposite directions<BR>\n" );
document.write( "add up speeds<BR>\n" );
document.write( "4+3=7 km/hr<BR>\n" );
document.write( "..<BR>\n" );
document.write( "distance = 14 km<BR>\n" );
document.write( "...<BR>\n" );
document.write( "t= d/r<BR>\n" );
document.write( "t= 14/7<BR>\n" );
document.write( "t= 2<BR>\n" );
document.write( "After 2 hours they will be 14 km apart<BR>\n" );
document.write( "...<BR>\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );