document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=5315>Question 5315</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello I'm very poor when it comes to math I trying to brush up on my algebra skills\r<BR>\n" );
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document.write( "When evaluating I have to solve for x\r<BR>\n" );
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document.write( "34 - 10x=6x+2\r<BR>\n" );
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document.write( "Here is my work:\r<BR>\n" );
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document.write( "34 - 10x=6x+2\r<BR>\n" );
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document.write( "34 - 10x + 10x=6x+2\r<BR>\n" );
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document.write( "2+34=6x+2 \r<BR>\n" );
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document.write( "36=6x and from here I lost the pro\r<BR>\n" );
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document.write( "Also I have problems include letters this is really confusing<BR>\n" );
document.write( "ex. <BR>\n" );
document.write( "b +ax =c<BR>\n" );
document.write( "ax = bx +c <BR>\n" );
document.write( "ax - b = cx + d \r<BR>\n" );
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document.write( " The book I'm using is not really clear on the subject, \"Algebra the easy wasy\" 3rd edition\r<BR>\n" );
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document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2698 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2698\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> right then....\r<BR>\n" );
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document.write( "First, algebra is very simple in the fact that there are only a few simple rules to remember and you apply them. You do not apply your version of the rules :-)\r<BR>\n" );
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document.write( "With equations - one side equals the other side, like a balance. What you do to one side, you have to do to the other side, to keep that balance. So, we need to end up with x=answer (or strictly, 1x=answer)\r<BR>\n" );
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document.write( "34 - 10x = 6x + 2 --> we will remove the +6x term from the right hand side. How? by subtracting 6x from both sides:\r<BR>\n" );
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document.write( "34 - 10x -6x = 6x + 2 -6x<BR>\n" );
document.write( "34 - 16x = 2 --> Now we will remove the +34 from the left hand side. How? By subtracting 34 from both sides:\r<BR>\n" );
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document.write( "34 - 16x - 34 = 2 - 34<BR>\n" );
document.write( "-16x = -32 --> now we want to convert the -16x into 1x. Note the x is unchanged, so we need to figure out how to manipulate the -16 by itself and convert it into a 1. Answer is to divide by -16, since -16/-16 is 1. And we do the same to both side remember:\r<BR>\n" );
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document.write( "-16x/-16 = -32/-16<BR>\n" );
document.write( "--> x = 2\r<BR>\n" );
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document.write( "That is your answer.\r<BR>\n" );
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document.write( "ANY further question you are liable to do in algebra using the same simple approach as this.\r<BR>\n" );
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document.write( "I do not understand what you want to do with the other equation. Please explain. Or better, you have a go first then send in your answer to me to check.\r<BR>\n" );
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document.write( "jon.<BR>\n" );
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