document.write( "Question 380090: Determine the amount of a 25% acid solution and a 80% acid solution needed to make 250 mL of a 40% acid solution. \n" ); document.write( "
Algebra.Com's Answer #269774 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Determine the amount of a 25% acid solution and a 80% acid solution needed to make 250 mL of a 40% acid solution. \n" ); document.write( "--------------------------- \n" ); document.write( "Equation: \n" ); document.write( "acid + acid = acid \n" ); document.write( "0.25x + 0.80(250-x) = 0.40*250 \n" ); document.write( "--- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "25x + 80*250 - 80x = 40*250 \n" ); document.write( "---- \n" ); document.write( "-55x = -40*250 \n" ); document.write( "x = 181.82mL (amt. of 25% solution needed in the mixture) \n" ); document.write( "---- \n" ); document.write( "250-181.82 = 68.18mL (amt. of 80% solution needed in the mixture) \n" ); document.write( "========================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |