document.write( "Question 380090: Determine the amount of a 25% acid solution and a 80% acid solution needed to make 250 mL of a 40% acid solution. \n" ); document.write( "
Algebra.Com's Answer #269774 by stanbon(75887)\"\" \"About 
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Determine the amount of a 25% acid solution and a 80% acid solution needed to make 250 mL of a 40% acid solution.
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\n" ); document.write( "Equation:
\n" ); document.write( "acid + acid = acid
\n" ); document.write( "0.25x + 0.80(250-x) = 0.40*250
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\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "25x + 80*250 - 80x = 40*250
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\n" ); document.write( "-55x = -40*250
\n" ); document.write( "x = 181.82mL (amt. of 25% solution needed in the mixture)
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\n" ); document.write( "250-181.82 = 68.18mL (amt. of 80% solution needed in the mixture)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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