document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=41723>Question 41723</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Simplify.\r<BR>\n" );
document.write( "\n" );
document.write( "-125 to the -3/2 power </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #26976 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=26976\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Okay, we can express -125 as (-5)^3, so we have<BR>\n" );
document.write( "(-125)^(-3/2) =<BR>\n" );
document.write( "((-5)^3)^(-3/2) =<BR>\n" );
document.write( "(-5)^(-9/2) = <BR>\n" );
document.write( "1 / (-5)^(9/2) =<BR>\n" );
document.write( "1 / [(-5)^4 * (-5)^(1/2)] =<BR>\n" );
document.write( "1 / 625i*sqrt(5)<BR>\n" );
document.write( "Now we have to rationalize by multiplying top and bottom by -i*sqrt(5) and we get<BR>\n" );
document.write( "-i*sqrt(5) / 3125 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );